TSTP Solution File: ITP209^4 by Duper---1.0
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% File : Duper---1.0
% Problem : ITP209^4 : TPTP v8.1.2. Released v8.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n028.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 03:39:20 EDT 2023
% Result : Theorem 5.30s 5.49s
% Output : Proof 5.30s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.11/0.11 % Problem : ITP209^4 : TPTP v8.1.2. Released v8.0.0.
% 0.11/0.13 % Command : duper %s
% 0.12/0.34 % Computer : n028.cluster.edu
% 0.12/0.34 % Model : x86_64 x86_64
% 0.12/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.12/0.34 % Memory : 8042.1875MB
% 0.12/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.12/0.34 % CPULimit : 300
% 0.12/0.34 % WCLimit : 300
% 0.12/0.34 % DateTime : Sun Aug 27 10:58:38 EDT 2023
% 0.12/0.34 % CPUTime :
% 5.30/5.49 SZS status Theorem for theBenchmark.p
% 5.30/5.49 SZS output start Proof for theBenchmark.p
% 5.30/5.49 Clause #1 (by assumption #[]): Eq (∀ (A2 B2 : a), Eq (f A2 B2) (f B2 A2)) True
% 5.30/5.49 Clause #2 (by assumption #[]): Eq (∀ (A2 B2 C : a), Eq (f A2 (f B2 C)) (f B2 (f A2 C))) True
% 5.30/5.49 Clause #12 (by assumption #[]): Eq (Not (Eq (f (f a2 b) c) (f (f a2 c) b))) True
% 5.30/5.49 Clause #50 (by clausification #[1]): ∀ (a_1 : a), Eq (∀ (B2 : a), Eq (f a_1 B2) (f B2 a_1)) True
% 5.30/5.49 Clause #51 (by clausification #[50]): ∀ (a_1 a_2 : a), Eq (Eq (f a_1 a_2) (f a_2 a_1)) True
% 5.30/5.49 Clause #52 (by clausification #[51]): ∀ (a_1 a_2 : a), Eq (f a_1 a_2) (f a_2 a_1)
% 5.30/5.49 Clause #130 (by clausification #[2]): ∀ (a_1 : a), Eq (∀ (B2 C : a), Eq (f a_1 (f B2 C)) (f B2 (f a_1 C))) True
% 5.30/5.49 Clause #131 (by clausification #[130]): ∀ (a_1 a_2 : a), Eq (∀ (C : a), Eq (f a_1 (f a_2 C)) (f a_2 (f a_1 C))) True
% 5.30/5.49 Clause #132 (by clausification #[131]): ∀ (a_1 a_2 a_3 : a), Eq (Eq (f a_1 (f a_2 a_3)) (f a_2 (f a_1 a_3))) True
% 5.30/5.49 Clause #133 (by clausification #[132]): ∀ (a_1 a_2 a_3 : a), Eq (f a_1 (f a_2 a_3)) (f a_2 (f a_1 a_3))
% 5.30/5.49 Clause #139 (by superposition #[133, 52]): ∀ (a_1 a_2 a_3 : a), Eq (f a_1 (f a_2 a_3)) (f a_2 (f a_3 a_1))
% 5.30/5.49 Clause #177 (by superposition #[139, 52]): ∀ (a_1 a_2 a_3 : a), Eq (f (f a_1 a_2) a_3) (f a_2 (f a_3 a_1))
% 5.30/5.49 Clause #1572 (by clausification #[12]): Eq (Eq (f (f a2 b) c) (f (f a2 c) b)) False
% 5.30/5.49 Clause #1573 (by clausification #[1572]): Ne (f (f a2 b) c) (f (f a2 c) b)
% 5.30/5.49 Clause #1574 (by forward demodulation #[1573, 177]): Ne (f b (f c a2)) (f (f a2 c) b)
% 5.30/5.49 Clause #1575 (by forward demodulation #[1574, 133]): Ne (f c (f b a2)) (f (f a2 c) b)
% 5.30/5.49 Clause #1576 (by forward demodulation #[1575, 177]): Ne (f c (f b a2)) (f c (f b a2))
% 5.30/5.49 Clause #1577 (by eliminate resolved literals #[1576]): False
% 5.30/5.49 SZS output end Proof for theBenchmark.p
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